Chapter 14 Acid Base Equilibria
Chapter 14 Key Equations
[latex]K_w = [H_3O^+][OH^-] = 1.0 \times 10^{-14}[/latex] (at 25°C) |
[latex]\text {pH} = - \log [H_3O^+][/latex] |
[latex]\text {pOH} = -\log [OH^-][/latex] |
[latex]\text {pH} + \text {pOH} = \text pK_w = 14.00[/latex] (at 25°C) |
[latex]K_a \, K_b = K_w = 1.0 \times 10^{-14}[/latex] |
[latex]percent \; ionization = \frac {[H_3O^+]_{eq}}{[HA]_o} \times 100 \%[/latex] |
[latex]\text pK_a = - \log {K_a}[/latex] |
[latex]\text pK_b = -\log {K_b}[/latex] |
[latex]\text {pH} = \text pK_a + \log \frac {[A^-]}{[HA]}[/latex] |